Three vectors satisfy the relation $\overrightarrow{A}.\overrightarrow{B}=0$ and $\overrightarrow{A}.\overrightarrow{C}=0$ then $\overrightarrow{A}$ is parallel to
Here $\overrightarrow{A} .{B}$ =$AB\, cos \theta$ = $AB\, cos 90^\circ$ = O $\Rightarrow$ $\overrightarrow{A} \perp \overrightarrow{B}$
Similarly, $\overrightarrow{A} \perp \overrightarrow{C} \Rightarrow \overrightarrow{B}$ and $ \overrightarrow{C}$ are in the same plane and
$ \overrightarrow{A}$ is perpendicular to them.
Thus $ \overrightarrow{A} || \overrightarrow{B} \times \overrightarrow{C}$
Was this answer helpful?
7
0
Top Questions on System of Particles & Rotational Motion
The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.