Question:
Three separate samples of a solution of a single salt gave these results. One formed a white precipitate with excess ammonia solution, one formed a white precipitate with dil. $HCl$ solution and one formed a black precipitate with $H_{2} S$. The salt could be
Three separate samples of a solution of a single salt gave these results. One formed a white precipitate with excess ammonia solution, one formed a white precipitate with dil. $HCl$ solution and one formed a black precipitate with $H_{2} S$. The salt could be
Updated On: Jan 30, 2025
- $AgNO_3$
- $Pb(NO_3)_2$
- $Hg(NO_3)_2$
- $MnSO_4$
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The Correct Option is B
Solution and Explanation
The salt could be $Pb \left( NO _{3}\right)_{2}$
It formed a white precipitate with excess ammonia solution:
$Pb \left( NO _{3}\right)_{2}+2 NH _{4} OH \rightarrow Pb ( OH )_{2} \downarrow$ (white ppt) $+2 NH _{4} NO _{3}$
It formed a white precipitate with dil. $NaCl$ solution:
$Pb \left( NO _{3}\right)_{2}+2 NaCl \rightarrow PbCl _{2} \downarrow$ (white ppt) $+2 NaNO _{3}$
It formed a black precipitate with $H _{2} S$ :
$Pb \left( NO _{3}\right)_{2}+ H 2 S \rightarrow PbS \downarrow$ (black ppt) $+2 HNO _{3}$
It formed a white precipitate with excess ammonia solution:
$Pb \left( NO _{3}\right)_{2}+2 NH _{4} OH \rightarrow Pb ( OH )_{2} \downarrow$ (white ppt) $+2 NH _{4} NO _{3}$
It formed a white precipitate with dil. $NaCl$ solution:
$Pb \left( NO _{3}\right)_{2}+2 NaCl \rightarrow PbCl _{2} \downarrow$ (white ppt) $+2 NaNO _{3}$
It formed a black precipitate with $H _{2} S$ :
$Pb \left( NO _{3}\right)_{2}+ H 2 S \rightarrow PbS \downarrow$ (black ppt) $+2 HNO _{3}$
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