\(F_{AC} = \frac{k(5 \times 0.3) \times 10^{-12}}{9 \times 10^{-4}}\)
\(F_{AB} = \frac{k(5 \times 0.16)\times 10^{-12}}{9\times 10^{-4}}\)
\(F_{net} = \frac{k \times 10^{-12}}{9\times 10^{-4}} \sqrt{1.5^2+(0.8)^2}\)
= \(\frac{10^9 \times 10^{-12}}{10^{-4} \times 1.7}\)
= \(17\)
Two point charges M and N having charges +q and -q respectively are placed at a distance apart. Force acting between them is F. If 30% of charge of N is transferred to M, then the force between the charges becomes:
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)
It is the property of subatomic particles that experiences a force when put in an electric and magnetic field. It is are of two types: Positive and Negative. It commonly carried by charge carriers protons and electrons.
Various properties of charge include the following :-
Two kinds of electric charges are there :-
When there is an identical number of positive and negative charges, the negative and positive charges would cancel out each other and the object would become neutral.