When amplifiers are cascaded, the total voltage gain is the product of the individual gains. The voltage gain in dB is given by:
\[
A_{dB} = 20 \log_{10} \left( \text{Total Voltage Gain} \right)
\]
For three amplifiers with individual gains of 50, the total voltage gain is:
\[
\text{Total Voltage Gain} = 50 \times 50 \times 50 = 125000
\]
Now, converting this to dB:
\[
A_{dB} = 20 \log_{10}(125000) \approx 98 \, \text{dB}
\]
Thus, the correct answer is option (3).