Three identical amplifiers with each one having a voltage gain of 50, input resistance of 1 kΩ and output resistance of 250 Ω are cascaded. The open circuit voltage gain of the combined amplifier is
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For cascaded amplifiers, the total gain is the product of the individual gains, and the total dB gain is calculated using \( 20 \log_{10}(\text{Total Gain}) \).
When amplifiers are cascaded, the total voltage gain is the product of the individual gains. The voltage gain in dB is given by:
\[
A_{dB} = 20 \log_{10} \left( \text{Total Voltage Gain} \right)
\]
For three amplifiers with individual gains of 50, the total voltage gain is:
\[
\text{Total Voltage Gain} = 50 \times 50 \times 50 = 125000
\]
Now, converting this to dB:
\[
A_{dB} = 20 \log_{10}(125000) \approx 98 \, \text{dB}
\]
Thus, the correct answer is option (3).