Three girls Reshma, Salma and Mandip are playing a game by standing on a circle of radius 5m drawn in a park. Reshma throws a ball to Salma, Salma to Mandip, Mandip to Reshma. If the distance between Reshma and Salma and between Salma and Mandip is 6m each, what is the distance between Reshma and Mandip?
Solution and Explanation
Draw perpendiculars OA and OB on RS and SM respectively.
AR=AS= \(\frac{6}{2}\) =3 m
OR = OS = OM = 5 m. (Radii of the circle)
In ∆OAR,
OA2 + AR2 = OR2
OA2 + (3 m)2 = (5 m)2
OA2 = (25 − 9) m2 = 16 m2
OA = 4m
ORSM will be a kite (OR = OM and RS = SM). We know that the diagonals of a kite are perpendicular and the diagonal common to both the isosceles triangles is bisected by another diagonal.
∠RCS will be of 90° and ∠RC = ∠CM
Area of ∆ORS = \(\frac{1}{2}\)× OA×RS
\(\frac{1}{2}\)×RC×OS= \(\frac{1}{2}\)×4×6
RC×5=24
RC=4.8
RM=2RC
=2(4.8)=9.4
Therefore, the distance between Reshma and Mandip is 9.6 m.
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