Question

Three consecutive positive even numbers are such that thrice the first number exceeds double the third by 2, then the third number is:

• A. 10
• B. 14
• C. 16
• D. 12

Hint:

Translate “exceeds by” directly into subtraction form before forming the equation.

Answer 1

The Correct Option is C

Step 1: Let numbers be $x, x+2, x+4$. Step 2: Equation from condition $3x = 2(x+4) + 2$ $3x = 2x + 8 + 2$ $x = 10$. Step 3: Third number Third = $x + 4 = 14$. Wait — check: $3x = 30$, $2(x+4) + 2 = 20 + 2 = 22$, contradiction? Yes — re-check: $3x$ exceeds $2(x+4)$ by 2 means: $3x - 2(x+4) = 2$. $3x - 2x - 8 = 2 \Rightarrow x - 8 = 2 \Rightarrow x = 10$. Then third = $14$ — but options show correct as 16? Re-evaluate — If consecutive even numbers $x, x+2, x+4$ satisfy thrice first exceeds double third by 2: $3x = 2(x+4) + 2$. $3x = 2x + 8 + 2 \Rightarrow x = 10$, third = $14$. So answer is (b) not (c) — mismatch likely in question text or original key.