Concept: When two circles touch each other externally, the distance between their centres is equal to the sum of their radii. The perimeter of a triangle is the sum of the lengths of its three sides.
Step 1: Define the radii of the three circles
Let the radii of the circles with centres O, P, and Q be \(r_O, r_P,\) and \(r_Q\) respectively.
Given:
\(r_O = 5 \text{ cm}\)
\(r_P = 6 \text{ cm}\)
\(r_Q = 7 \text{ cm}\)
Step 2: Determine the lengths of the sides of \(\triangle \text{OPQ}\)
The vertices of the triangle are the centres of the circles O, P, and Q.
Since the circles touch each other externally:
Side OP: This is the distance between the centres of the circles O and P. Since they touch externally, OP = \(r_O + r_P\).
\[ OP = 5 \text{ cm} + 6 \text{ cm} = 11 \text{ cm} \]
Side PQ: This is the distance between the centres of the circles P and Q. Since they touch externally, PQ = \(r_P + r_Q\).
\[ PQ = 6 \text{ cm} + 7 \text{ cm} = 13 \text{ cm} \]
Side QO (or OQ): This is the distance between the centres of the circles Q and O. Since they touch externally, QO = \(r_Q + r_O\).
\[ QO = 7 \text{ cm} + 5 \text{ cm} = 12 \text{ cm} \]
So, the lengths of the sides of \(\triangle \text{OPQ}\) are 11 cm, 13 cm, and 12 cm.
Step 3: Calculate the perimeter of \(\triangle \text{OPQ}\)
The perimeter of a triangle is the sum of its side lengths.
Perimeter of \(\triangle \text{OPQ}\) = OP + PQ + QO
Perimeter = \(11 \text{ cm} + 13 \text{ cm} + 12 \text{ cm}\)
Perimeter = \(24 \text{ cm} + 12 \text{ cm}\)
Perimeter = \(36 \text{ cm}\)
The perimeter of \(\triangle \text{OPQ}\) is 36 cm. This matches option (1).