Let’s analyze the forces acting on each block.
For the system as a whole (masses \(M_1\), \(M_2\), and \(M_3\) together) moving upwards with an acceleration \(a = 2 \, \mathrm{m/s^2}\):
Total mass, \(M = M_1 + M_2 + M_3 = 4 + 6 + 10 = 20 \, \mathrm{kg}.\)
Total weight, \(W = Mg = 20 \times 10 = 200 \, \mathrm{N}\)
Since the entire system is accelerating upwards, the net force \(F\) required to produce this acceleration is given by:
\(F = Ma = 20 \times 2 = 40 \, \mathrm{N}\)
Thus, the tension \(T_1\) in rope 1 must support both the weight and the additional force required for acceleration:
\(T_1 = W + F = 200 + 40 = 240 \, \mathrm{N}\)
The driver sitting inside a parked car is watching vehicles approaching from behind with the help of his side view mirror, which is a convex mirror with radius of curvature \( R = 2 \, \text{m} \). Another car approaches him from behind with a uniform speed of 90 km/hr. When the car is at a distance of 24 m from him, the magnitude of the acceleration of the image of the side view mirror is \( a \). The value of \( 100a \) is _____________ m/s\(^2\).
An alphabet 'a' made of two similar thin uniform metal plates of each length \( L \) and width \( a \) is placed on a horizontal surface as shown in the figure. If the alphabet is vertically inverted, the shift in the position of its center of mass from the horizontal surface is: