Question:

Thirty women were examined in a hospital by a doctor and the number of heartbeats per minute were recorded and summarised as follows. Find the mean heartbeats per minute for these women, choosing a suitable method.

Number of heartbeats per minute65 - 6868 - 7171 - 7474 - 7777 - 8080 - 8383 - 86
Number of boxs2438742

Updated On: Nov 8, 2023
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Solution and Explanation

To find the class mark (\(x_i\)) for each interval, the following relation is used.  

Class mark  \((x_i)\) = \(\frac {\text{Upper \,limit + Lower \,limit}}{2}\)

class size (h) of the data =  3 

Taking 75.5 as assumed mean (a), \(d_i\)\(u_i\), and \(f_iu_i\) can be calculated as follows.   

Number of heart beats per minute Number of women (\(\bf{f_i}\))            \(\bf{x_i}\)       \(\bf{d_i = x_i -75.5}\)\(\bf{u_i = \frac{d_i}{3}}\)       \(\bf{f_iu_i}\)          

65 - 68

2

66.5

-9

-3

-6

68 - 71

4

69.5

-6

-2

-8

71 -74

3

72.5

-3

-1

-1

74 - 77

8

75.5

-3

-1

-3

77 - 80

7

78.5

3

1

7

80 - 83

7

78.5

3

1

7

83 - 86

2

84.5

9

3

6

Total 

30

 

  

4

From the table, it can be observed that  

\(\sum f_i = 30\)
\(\sum f_iu_i = 4\)

Mean, \(\overset{-}{x} = a + (\frac{\sum f_iu_i}{\sum f_i})h\) 

x = \(75.5 + (\frac{4 }{30}) \times 20\) 

x = 75.5 - \((\frac{4}{30}) \times 3\) 

x = 75.5 + 0.4

x = 75.9

Therefore, mean hear beats per minute for these women are 75.9 beats per minute.

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