Step 1: Understanding the Concept:
This problem involves calculating the probability of two independent events occurring together. The outcome of drawing a ball from the first bag does not affect the outcome of drawing a ball from the second bag. For independent events, the probability that both occur is the product of their individual probabilities.
Step 2: Key Formula or Approach:
Let A be the event of drawing a black ball from the first bag, and B be the event of drawing a black ball from the second bag.
The probability of an event is given by:
\[ P(\text{Event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \]
Since the events are independent, the probability of both events occurring is:
\[ P(A \text{ and } B) = P(A) \times P(B) \]
Step 3: Detailed Explanation or Calculation:
First Bag:
Total number of balls = 4 white + 2 black = 6 balls.
Number of black balls = 2.
The probability of drawing a black ball from the first bag is \( P(A) \).
\[ P(A) = \frac{\text{Number of black balls}}{\text{Total number of balls}} = \frac{2}{6} = \frac{1}{3} \]
Second Bag:
Total number of balls = 3 white + 5 black = 8 balls.
Number of black balls = 5.
The probability of drawing a black ball from the second bag is \( P(B) \).
\[ P(B) = \frac{\text{Number of black balls}}{\text{Total number of balls}} = \frac{5}{8} \]
Combined Probability:
The probability of getting a black ball from both bags is the product of the individual probabilities.
\[ P(\text{both black}) = P(A) \times P(B) = \frac{1}{3} \times \frac{5}{8} = \frac{5}{24} \]
Step 4: Final Answer:
The probability of getting both black balls is \( \frac{5}{24} \).