92
If there are 10 stations, the number of ways to choose two distinct stations (i.e., the number of possible journeys between two stations) is given by the combination formula \( \binom{n}{2} \), where \( n \) is the total number of stations.
Thus, the number of different journey tickets is:
\[ \binom{10}{2} = \frac{10 \times 9}{2} = 45 \]
This is the number of possible journeys in one direction. Since a ticket can be for a journey in either direction (forward or backward), we multiply by 2:
\[ 45 \times 2 = 90 \]
Thus, the number of different journey tickets required is 90.