Question

The zeroes of the polynomial \(x^{2}-16\) are

• A. \(+4,-4\)
• B. \(+4,+4\)
• C. \(-4,-4\)
• D. none of these

Hint:

Remember \(a^{2}-b^{2}=(a-b)(a+b)\) to factor quickly.

Answer 1

The Correct Option is A

Step 1: Factorize as difference of squares.
\(x^{2}-16=(x-4)(x+4)\).
Step 2: Set each factor to zero.
\(x=4\) or \(x=-4\).