Question:

The work done in pulling up a block of wood weighing $ 2\,\,kN $ for a length of $ 10\,\,m $ on a smooth plane inclined at an angle of $ {{15}^{o}} $ with the horizontal is:

Updated On: Aug 1, 2022
  • $ 9.82\,\,kJ $
  • $ 89\,\,kJ $
  • $ 4.35\,\,kJ $
  • $ 5.17\,\,kJ $
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The Correct Option is D

Solution and Explanation

Here : weight of block $w=2 \,kN$, Distance $d=10\, m$ Angle of inclination on the plane $\alpha=15^{\circ}$ The block will be pulled up on a smooth plane Hence, force of resistance due to inclination $F =w \sin \alpha=2 \times 10^{3} \sin 15^{\circ} $ $=2 \times 10^{3} \times 0.2588 $ $=0.5176 \,kN$ Now work done, $W =F d=0.5176 \times 10^{3} \times 10$ $=5: 17\, kN$
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Concepts Used:

Work-Energy Theorem

The work and kinetic energy principle (also known as the work-energy theorem) asserts that the work done by all forces acting on a particle equals the change in the particle's kinetic energy. By defining the work of the torque and rotational kinetic energy, this definition can be extended to rigid bodies.

The change in kinetic energy KE is equal to the work W done by the net force on a particle is given by,

W = ΔKE = ½ mv2f − ½ mv2i

Where, 

vi → Speeds of the particle before the application of force

vf → Speeds of the particle after the application of force

m → Particle’s mass

Note: Energy and Momentum are related by, E = p2 / 2m.