
From the graph, we observe that the area under the power-time graph represents the work done on the particle.
The momentum \( p \) of the particle at time \( t = 5 \, \text{s} \) can be calculated from the work done.
Using the relationship \(p^2 = 2 \times 500 \times 10^3\), the momentum is found to be \(5 \), \(\text{kg.m/s}\) .
The corresponding force is \(5.5 , \text{N} .\)

The circuit shown in the figure contains two ideal diodes \( D_1 \) and \( D_2 \). If a cell of emf 3V and negligible internal resistance is connected as shown, then the current through \( 70 \, \Omega \) resistance (in amperes) is: 