Question:

The work done in blowing a soap bubble of surface tension $ 0.06 ??Nm^{-1}$ from $2 \,cm$ radius to $5 \,cm$ radius is.

Updated On: Jan 30, 2025
  • 0.004168 J
  • 0.003168 J
  • 0.003158 J
  • 0.004568 J
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The Correct Option is B

Solution and Explanation

$\Delta W = S \times\Delta A$ $ = 0.06 \times4\pi\left(r^{2}_{2} - r^{2}_{1}\right)$ $ = 0.003168 \,J $
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Concepts Used:

Surface Tension

The amount of energy required to increase the liquid's surface area by one unit area is known as surface tension. In other words, it is a property of the liquid surface to resist force.

Surface tension is defined as,

The ratio of the surface force F to the length L along which the force acts.

Mathematically, the surface tension formula can be expressed as follows:

T=F/L

Where,

  • F is the force per unit length
  • L is the length in which force act
  • T is the surface tension of the liquid

Read More: Detergents and Surface Tension

Factors affecting surface tension:

  • Impurities: The surface tension decreases with the addition of impurities.
  • Surfactants: Adding surfactants in liquids lowers the tension of water making it interrupt aside or get susceptible.
  • Temperature: The surface tension of a liquid reduces as the temperature rises.

The Unit of Surface Tension:

The SI unit of Surface Tension is Newton per Meter or N/m.