The width of river is 1 km. The velocity of boat is 5 km/hr. The boat covered the width of river with shortest will possible path in 15 min. Then the velocity of river stream is:
\(3 \ km/hr\)
\(4 \ km/hr\)
\(\sqrt {29} \ km/hr\)
\(\sqrt {41} \ km/hr\)
\(t=\frac {d}{\sqrt {υ^2-v^2}}\)
\(\frac 14= \frac {1}{\sqrt {(5)^2-v^2}}\)
\(\frac {1}{16} = \frac {1}{25-v^2}\)
\(25-v^2 = 16\)
\(v^2 = 9\)
\(v =\sqrt {9}\)
\(v=3\ km/hr\)
So, the correct option is (A): \(3\ km/hr\)
The current passing through the battery in the given circuit, is:
A bob of heavy mass \(m\) is suspended by a light string of length \(l\). The bob is given a horizontal velocity \(v_0\) as shown in figure. If the string gets slack at some point P making an angle \( \theta \) from the horizontal, the ratio of the speed \(v\) of the bob at point P to its initial speed \(v_0\) is :
A full wave rectifier circuit with diodes (\(D_1\)) and (\(D_2\)) is shown in the figure. If input supply voltage \(V_{in} = 220 \sin(100 \pi t)\) volt, then at \(t = 15\) msec:
It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions.
The equations of motion in a straight line are:
v=u+at
s=ut+½ at2
v2-u2=2as
Where,