Question

A capacitor and a coil with resistance R are in series and connected to a 6 V AC source. By varying the frequency of the source, a maximum current of 600 mA is observed. If the same coil is now connected to a cell of emf 6 V and internal resistance of 2 ohms, the current through it will be:

• A. 0.6 A
• B. 0.5 A
• C. 1.0 A
• D. 2.0 A

Answer 1

The Correct Option is B

Given AC circuit scenario:

Series RLC circuit with 6V AC source shows maximum current (I_max) = 600 mA at resonance.

Step 1: Determine coil resistance (R)

At resonance (maximum current): \[ I_{max} = \frac{V}{Z} = \frac{V}{R} \] \[ 0.6 = \frac{6}{R} \Rightarrow R = 10\ \Omega \]

Step 2: Analyze DC scenario

When connected to 6V DC source with internal resistance (r) = 2Ω: \[ I = \frac{V}{R + r} = \frac{6}{10 + 2} = 0.5\ \text{A} \]

Final answer: The current through the coil will be 0.5 A.