The correct option is (C): 26.16 kg
To find the weight of the solid cone, we can use the formula for the volume of a cone and then multiply it by the density of the material.
Steps to Solve:
1. **Formula for the Volume of a Cone**:
\[V = \frac{1}{3} \pi r^2 h \]
Where:
\( r \) = radius of the cone
\( h \) = height of the cone
2. Given Values:
- Diameter = 14 cm, so the radius \( r = \frac{14}{2} = 7 \) cm
- Height \( h = 51 \) cm
- Density of the material = 10 grams/cm³
3. Calculating the Volume:
\[V = \frac{1}{3} \pi (7^2)(51)\]
\[V = \frac{1}{3} \pi (49)(51)\]
\[V = \frac{1}{3} \pi (2499)\]
\[V \approx \frac{1}{3} \times 3.14 \times 2499\]
\[V \approx \frac{1}{3} \times 7847.86 \approx 2615.95 \, \text{cm}^3\]
4. Calculating the Weight:
\[\text{Weight} = \text{Volume} \times \text{Density}\]
\[\text{Weight} = 2615.95 \, \text{cm}^3 \times 10 \, \text{grams/cm}^3\]
\[\text{Weight} \approx 26159.5 \, \text{grams}\]
5. Converting grams to kilograms:
\[\text{Weight} \approx \frac{26159.5}{1000} \approx 26.16 \, \text{kg}\]
Conclusion:
The weight of the solid cone is approximately 26.16 kg.
In the given figure, the numbers associated with the rectangle, triangle, and ellipse are 1, 2, and 3, respectively. Which one among the given options is the most appropriate combination of \( P \), \( Q \), and \( R \)?
