Question

The volume of carbon dioxide gas evolved at S.T.P. by heating $7.3\, gm$ of $Mg \left( HCO _{3}\right)_{2}$ will be

• A. 2240 ml
• B. 1120 ml
• C. 2340 ml
• D. 2000 ml.

Answer 1

The Correct Option is B

$Mg\left(HCO_{3}\right)_{2} \to MgO + 2CO_{2} + H_{2}O$ $146 \,g$ give $22.4$ Litre of $CO_{2}$ $\Rightarrow 7.3 \,g$ will give $= \frac{22.4}{146}\times7.3$ $\Rightarrow = 1.12$ litre of $CO_{2}$ $= 1120\, ml$ of $CO_{2}$