Question

The volume occupied by the molecules contained in 4.5 kg water at STP, if the intermolecular forces vanish away is:

• A. 5.6 × 10⁶ m³
• B. 56 × 10⁶ m³
• C. 5.6 × 10^-3 m³
• D. 5.6 m³

Answer 1

The Correct Option is D

The problem requires us to calculate the volume occupied by the molecules in 4.5 kg of water at STP if intermolecular forces disappear. We begin with the basic understanding that water is H₂O, and the molar mass of H₂O is roughly 18 g/mol. Therefore, we first convert 4.5 kg of water into moles.

Step 1: Convert Mass to Moles

\( m_{\text{water}} = 4.5 \, \text{kg} = 4500 \, \text{g} \)

\( n = \frac{m_{\text{water}}}{M_{\text{H}_2\text{O}}} = \frac{4500 \, \text{g}}{18 \, \text{g/mol}} = 250 \, \text{mol} \)

Step 2: Calculate Volume Using Avogadro's Law

According to Avogadro's law, 1 mole of any ideal gas occupies \( 22.4 \, \text{L} \) at STP.

\( V = n \times 22.4 \, \text{L/mol} \) = \( 250 \, \text{mol} \times 22.4 \, \text{L/mol} = 5600 \, \text{L} \)

Convert liters to cubic meters:

\( V = \frac{5600}{1000} \, \text{m}^3 = 5.6 \, \text{m}^3 \)

Therefore, the volume occupied by the molecules is \( 5.6 \, \text{m}^3 \).