Question

The voltage \( V = 12 \, \text{V} \) (cos \( 60^\circ + 45^\circ \)) is applied to a \( 0.1 \, \text{H} \) inductor. Find the steady-state current through the inductor.

• A. \( i(t) = 2 \, \text{A} \cos(60^\circ + 45^\circ) \) A
• B. \( i(t) = 2 \, \text{A} \cos(60^\circ + 45^\circ) \) A
• C. \( i(t) = 5 \, \text{A} \cos(60^\circ + 45^\circ) \) A
• D. \( i(t) = 6 \, \text{A} \cos(60^\circ + 45^\circ) \) A

Hint:

In AC circuits with inductors, use phasor analysis to find the steady-state current.

Answer 1

The Correct Option is A

- Using the formula for the steady-state current in an RL circuit, we find that \( i(t) = 2 \, \text{A} \cos(60^\circ + 45^\circ) \) A.
Conclusion: The steady-state current is given by option (a).