Question:
The vertices of the hyperbola are at (-5,-3) and (-5,-1) and the extremities of the conjugate axis are at (-7,-2) and (-3,-2), then the equation of the hyperbola is
The vertices of the hyperbola are at (-5,-3) and (-5,-1) and the extremities of the conjugate axis are at (-7,-2) and (-3,-2), then the equation of the hyperbola is
Updated On: Sep 15, 2024
- \(\frac{(y-2)^2}{1}-\frac{(x-5)^2}{4}=1\)
- \(\frac{(y+2)^2}{1}-\frac{(x+5)^2}{4}=1\)
- \(\frac{(x+5)^2}{4}-\frac{(y+2)^2}{1}=1\)
- \(\frac{(x-5)^2}{4}-\frac{(y-2)^2}{1}=1\)
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The Correct Option is B
Solution and Explanation
The correct option is (B) : \(\frac{(y+2)^2}{1}-\frac{(x+5)^2}{4}=1\).
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