Question:
The vector equation of the line joining the points (2, 1, 3) and (-2, 4, 1) is
The vector equation of the line joining the points (2, 1, 3) and (-2, 4, 1) is
Updated On: Jun 10, 2024
- \(\overrightarrow{r} = 2\hat{i}+\hat{j}+3\hat{k}+\lambda(-4\hat{i}+3\hat{j}-2\hat{k})\)
- \(\overrightarrow{r} = 2\hat{i}+\hat{j}+3\hat{k}+\lambda(4\hat{i}+3\hat{j}+2\hat{k})\)
- \(\overrightarrow{r} = -2\hat{i}+\hat{j}+3\hat{k}+\lambda(-4\hat{i}-3\hat{j}-2\hat{k})\)
- \(\overrightarrow{r} = 2\hat{i}+\hat{j}+3\hat{k}+\lambda(3\hat{i}-4\hat{j}-2\hat{k})\)
- \(\overrightarrow{r} = -4\hat{i}+3\hat{j}-2\hat{k}+\lambda(2\hat{i}+\hat{j}+3\hat{k})\)
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(\overrightarrow{r} = 2\hat{i}+\hat{j}+3\hat{k}+\lambda(-4\hat{i}+3\hat{j}-2\hat{k})\)
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