The variation of acceleration due to gravity $g$ with distance $d$ from centre of the earth is best represented by (R = Earth?s radius) :
The Correct Option is D
Solution and Explanation
$d < R = g = \frac{Gm}{R^{2}} .d$
$ d=R =g_{s} = \frac{Gm}{R^{2}}$
$ d > R = g = \frac{Gm}{d^{2}} $
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Concepts Used:
Gravitation
In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
Newton’s Law of Gravitation
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
- F ∝ (M1M2) . . . . (1)
- (F ∝ 1/r2) . . . . (2)
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].