The variance of a set of numbers is calculated using the formula:
\[
\text{Variance} = \frac{\sum (x_i - \bar{x})^2}{n}
\]
Where:
- \( x_i \) are the data points,
- \( \bar{x} \) is the mean of the data,
- \( n \) is the number of data points.
The integers in question are 11, 12, 13, ..., 20. Let's calculate the mean first:
\[
\bar{x} = \frac{11 + 12 + 13 + 14 + 15 + 16 + 17 + 18 + 19 + 20}{10} = \frac{145}{10} = 14.5
\]
Now, calculate the sum of the squared differences from the mean:
\[
\sum (x_i - \bar{x})^2 = (11 - 14.5)^2 + (12 - 14.5)^2 + \cdots + (20 - 14.5)^2 = 14.5 + 6.25 + 2.25 + 0.25 + 0.25 + 2.25 + 6.25 \]
\[+ 12.25 + 20.25 + 30.25 = 100.5
\]
Finally, divide by the number of data points (10):
\[
\text{Variance} = \frac{100.5}{10} = 8.25
\]
Thus, the correct answer is 8.25.