The variance of the data \( 2, 4, 6, 8, 10 \) is:
Step 1: To calculate the variance, we use the formula: \[ {Variance} = \frac{1}{n} \sum_{i=1}^{n} (x_i - \mu)^2, \] where \( \mu \) is the mean of the data and \( n \) is the number of data points.
Step 2: Calculate the mean: \[ \mu = \frac{2 + 4 + 6 + 8 + 10}{5} = \frac{30}{5} = 6. \]
Step 3: Compute the squared differences from the mean: \[ (2 - 6)^2 = 16, \quad (4 - 6)^2 = 4, \quad (6 - 6)^2 = 0, \quad (8 - 6)^2 = 4, \quad (10 - 6)^2 = 16. \]
Step 4: Compute the variance: \[ {Variance} = \frac{16 + 4 + 0 + 4 + 16}{5} = \frac{40}{5} = 8. \]
If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :