The values of X, Y, and Z in the following chemical equation are respectively:
\( S_8 + X HNO_3 ({conc.}) \rightarrow Y H_2SO_4 + X NO_2 + Z H_2O \)
36, 6, 18
48, 8, 24
48, 8, 16
24, 8, 12
Step 1: Balance the reaction for sulfur \(S_8\), ensuring that the atoms on both sides are equal for all elements.
Step 2: Given that \(X = 48\), \(Y = 8\), and \(Z = 16\) implies each \(S\) in \(S_8\) reacts with 6 \(HNO_3\) to produce 1 \(H_2SO_4\) and 6 \(NO_2\), while 2 \(H_2O\) molecules are formed per \(S_8\) molecule.
Step 3: This stoichiometry provides a complete balance of the equation, satisfying conservation of mass and charge.
Step 4: Thus, the values \(X = 48\), \(Y = 8\), and \(Z = 16\) correctly balance the chemical equation.
Fortification of food with iron is done using $\mathrm{FeSO}_{4} .7 \mathrm{H}_{2} \mathrm{O}$. The mass in grams of the $\mathrm{FeSO}_{4} .7 \mathrm{H}_{2} \mathrm{O}$ required to achieve 12 ppm of iron in 150 kg of wheat is _______ (Nearest integer).} (Given : Molar mass of $\mathrm{Fe}, \mathrm{S}$ and O respectively are 56,32 and $16 \mathrm{~g} \mathrm{~mol}^{-1}$ )