Question

The value of the integral
\[ \int_{0.2}^{1.4} (\sin x - \log_e x + e^x) \, dx \]
using Simpson's three-eighth rule, by taking interval size \( h = 0.2 \), is:

• A. 4.05
• B. 4.052985
• C. 4.502985
• D. 4.052985

Hint:

Simpson’s three-eighth rule is a numerical integration technique that is particularly effective when dealing with irregular intervals and provides better accuracy for certain functions

Answer 1

The Correct Option is B

To apply Simpson’s three-eighth rule we use the given function values at the specified intervals and calculate the weighted sum The result of the integral is approximately 4.052985