Question:
The value of the integral \(\int e^x (logx + \frac{1}{x})dx\) is:
The value of the integral \(\int e^x (logx + \frac{1}{x})dx\) is:
Updated On: May 18, 2024
- \(e^xlog x + C\), Where C is a constant.
- \(e^{-x}log x + C\), Where C is a constant.
- \(\frac{e^x}{x} + C\), Where C is a constant.
- \(\frac{e^{-x}}{x} + C\), Where C is a constant.
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The Correct Option is A
Solution and Explanation
The correct option is (A): \(e^xlog x + C\), Where C is a constant.
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