The value of sin² 51° + sin² 39° is:
We know that \(\sin(90^\circ - x) = \cos(x)\).
Therefore, \(\sin(51^\circ) = \sin(90^\circ - 39^\circ) = \cos(39^\circ)\).
So, sin² 51° + sin² 39° = cos² 39° + sin² 39°
Using the trigonometric identity \(\sin^2(x) + \cos^2(x) = 1\), we get:
cos² 39° + sin² 39° = 1
Answer: (A) 1