Question:

The value of \(\log_6 2 + \log_6 3\) is:

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Remember that \(\log_b b = 1\) and use the product rule \(\log_b x + \log_b y = \log_b (x \times y)\) to simplify logarithmic expressions.
Updated On: Apr 18, 2025
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The Correct Option is B

Solution and Explanation

Using the logarithmic property \(\log_b x + \log_b y = \log_b (x \times y)\), we get: \[ \log_6 2 + \log_6 3 = \log_6 (2 \times 3) = \log_6 6 \] Since \(\log_b b = 1\), we have: \[ \log_6 6 = 1 \] Thus, the correct answer is 1.
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