Question

The value of F so as to keep the smooth wedge stationary, when it is loaded with a block of mass M, which is connected with a light inextensible string, will be

• (A) Mg sin 2θ
• (B) Mg/2 sin 2θ
• (C) Mg sin θ
• (D) Mg cos θ

Answer 1

The Correct Option is B

Explanation:

From the free body diagram of block,$N=Mg\cos \theta$From the free body diagram of wedge, for the horizontal direction, we have$F=N\sin \theta$Hence, $F=Mg\cos \theta \sin \theta$or$F=\frac{Mg}{2}\sin 2\theta$