Question

The value of \( E_0 \) is 9.3 V/m and \( c \) is \( 3 \times 10^8 \, \text{m/s} \). Find the value of \( B_0 \).

Answer 1

In electromagnetic waves, the relationship between the electric field \( E_0 \) and the magnetic field \( B_0 \) is given by: \[ c = \frac{E_0}{B_0}, \] where \( c \) is the speed of light in a vacuum, \( E_0 \) is the amplitude of the electric field, and \( B_0 \) is the amplitude of the magnetic field. Rearranging the formula to solve for \( B_0 \): \[ B_0 = \frac{E_0}{c}. \] Substitute the given values: \[ B_0 = \frac{9.3 \, \text{V/m}}{3 \times 10^8 \, \text{m/s}} = 3.1 \times 10^{-8} \, \text{T}. \] Thus, the value of \( B_0 \) is \( 3.1 \times 10^{-8} \, \text{T} \).