Question:
The value of C in Rolle's theorem where \(-\frac{π}{2}\)<C<\(\frac{π}{2}\) and \(f(x)=cos x\) on \([-\frac{π}{2},\frac{π}{2}]\) is equal to :
The value of C in Rolle's theorem where \(-\frac{π}{2}\)<C<\(\frac{π}{2}\) and \(f(x)=cos x\) on \([-\frac{π}{2},\frac{π}{2}]\) is equal to :
Updated On: Mar 12, 2025
- 0
- π
- \(\frac{π}{2}\)
- \(\frac{π}{4}\)
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The Correct Option is A
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The correct option is(A):0
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