Step 1: Rolle's Theorem guarantees that there exists at least one point \( c \) in the interval \( [0, \pi] \) where the derivative of \( f(x) \) is zero.
Step 2: To find \( c \), first compute the derivative of \( f(x) = e^x \sin x \). We get:
\[
f'(x) = e^x (\sin x + \cos x).
\]
Set \( f'(x) = 0 \), which gives \( \sin x + \cos x = 0 \). Solving this gives \( x = \frac{\pi}{2} \).
Final Answer:
\[
\boxed{\frac{\pi}{2}}
\]