Question

The equation of the tangent to the curve \(y=x^3-2x+1\) at \((1,0)\) is:

• A. \(y=x-1\)
• B. \(y=x+1\)
• C. \(y=-x+1\)
• D. \(y=x\)

Hint:

Tangent slope = derivative at the point.

Answer 1

The Correct Option is A

\[ \frac{dy}{dx}=3x^2-2 \Rightarrow m=1 \] Equation: \(y-0=1(x-1)\Rightarrow y=x-1\)