Question:

The value of \(\frac{\cot 45^\circ}{\sin 30^\circ + \cos 60^\circ}\) is

Updated On: May 7, 2024

2
-2
1
-1

Hide Solution

Verified By Collegedunia

The Correct Option is C

Solution and Explanation

The correct option is (C): 1

Was this answer helpful?

0

0

Top Questions on Trigonometry

Number of solutions in the interval \( [-2\pi, 2\pi] \) for the equation: \[ 2\sqrt{2} \cos^2 \theta + (2 - \sqrt{6}) \cos \theta - \sqrt{3} = 0 \]
- JEE Main - 2025
- Mathematics
- Trigonometry
View Solution
Let \( S = \{ x : \cos^{-1} x = \pi + \sin^{-1} x + \sin^{-1} (2x + 1) \ \). Then \[ \sum_{x \in S} (2x - 1)^2 \text{ is equal to:} \]
- JEE Main - 2025
- Mathematics
- Trigonometry
View Solution
If \[ \sum_{r=1}^{13} \frac{1}{\sin \frac{\pi}{4} + (r-1) \frac{\pi}{6}} \sin \frac{\pi}{4} + \frac{\pi}{6} = a \sqrt{3} + b, \quad a, b \in \mathbb{Z}, { then } a^2 + b^2 { is equal to:} \]
- JEE Main - 2025
- Mathematics
- Trigonometry
View Solution
If \[ \sum_{r=1}^{13} \frac{1}{\sin \frac{\pi}{4} + (r-1) \frac{\pi}{6}} \sin \frac{\pi}{4} + \frac{\pi}{6} = a \sqrt{3} + b, \quad a, b \in \mathbb{Z}, { then } a^2 + b^2 { is equal to:} \]
- JEE Main - 2025
- Mathematics
- Trigonometry
View Solution
The value of \( \cos \left( \frac{\pi}{6} + \cot^{-1}(-\sqrt{3}) \right) \) is:
- CBSE CLASS XII - 2025
- Mathematics
- Trigonometry
View Solution

View More Questions

Questions Asked in TS POLYCET exam

View More Questions