Question:
The value of \(∫_0^{2\pi} sin^{2}nxdx\), where \(n∈I\), is:
The value of \(∫_0^{2\pi} sin^{2}nxdx\), where \(n∈I\), is:
Updated On: Mar 12, 2025
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- \(\frac{\pi}{2}\)
- \(\pi\)
- \(2\pi\)
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The Correct Option is C
Solution and Explanation
The correct option is (C): \(\pi\)
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