- The settling time for a second-order system is approximated as
\[
T_s \approx \frac{4}{\zeta \omega_n}
\]
- From the poles at \( s = -1 \) and \( s = -100 \), the dominant pole is at \( s = -1 \).
\[
T_s \approx \frac{4}{1} = 4 \, \text{sec}
\]
Conclusion:
The correct settling time is given by option (b).