To determine the total number of \( \text{Mn=O} \) bonds in \( \text{Mn}_2\text{O}_7 \), we must first understand the structure of the compound.
\( \text{Mn}_2\text{O}_7 \) is known as manganese(VII) oxide. Its structure is characterized by two tetrahedral \( \text{MnO}_4 \) units connected by an oxygen bridge. In this compound, each manganese (Mn) atom is bonded to four oxygen atoms. Out of these, one oxygen atom serves as a bridge between the two Mn atoms, and the other three are terminal oxygens bonded to manganese, forming double bonds.
The structure can be described as:
For clarity, consider the structure:
From this structure, we can observe that there are exactly three double bonds for each manganese atom:
Thus, the total number of \( \text{Mn=O} \) bonds in \( \text{Mn}_2\text{O}_7 \) is 6.
Therefore, the correct answer to the question is 6.
Structure of \(Mn_2O_7\) is as :

\(∴\) There are total \(6\) \(M = O\) bonds are present in \(Mn_2O_7\) compound.
The correct answer is (C): \(6\)



Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.