Question:
The total number of lone pairs of electrons in NO\(_2\)F is ............
The total number of lone pairs of electrons in NO\(_2\)F is ............
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To count lone pairs, remember to account for the electrons that are not involved in bonding. Each fluorine and oxygen atom typically has 3 lone pairs.
Updated On: Dec 11, 2025
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Correct Answer: 8
Solution and Explanation
Step 1: Understanding the electron configuration.
The Lewis structure of NO\(_2\)F shows that nitrogen (N) forms a single bond with oxygen (O) and fluorine (F). Nitrogen has one lone pair of electrons, while oxygen and fluorine both have three lone pairs each.
Step 2: Counting the lone pairs.
- Nitrogen: 1 lone pair - Oxygen: 3 lone pairs - Fluorine: 3 lone pairs
So the total number of lone pairs is \( 1 + 3 + 3 = 8 \).
Step 3: Conclusion.
The total number of lone pairs of electrons in NO\(_2\)F is 8.
The Lewis structure of NO\(_2\)F shows that nitrogen (N) forms a single bond with oxygen (O) and fluorine (F). Nitrogen has one lone pair of electrons, while oxygen and fluorine both have three lone pairs each.
Step 2: Counting the lone pairs.
- Nitrogen: 1 lone pair - Oxygen: 3 lone pairs - Fluorine: 3 lone pairs
So the total number of lone pairs is \( 1 + 3 + 3 = 8 \).
Step 3: Conclusion.
The total number of lone pairs of electrons in NO\(_2\)F is 8.
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