Question

BF\(_3\) reacts readily with ...........

• A. C\(_6\)H\(_5\)N
• B. SnCl\(_2\)
• C. SO\(_3\)
• D. (C\(_6\)H\(_5\)N)–SnCl\(_2\)

Hint:

BF\(_3\) is a strong Lewis acid and reacts with Lewis bases like amines to form stable complexes.

Answer 1

The Correct Option is A, D

Step 1: Understanding BF\(_3\) reactivity.
BF\(_3\) is a Lewis acid and reacts with Lewis bases like amines (C\(_6\)H\(_5\)N), which can donate electron pairs.
Step 2: Analyzing the options.
(A) C\(_6\)H\(_5\)N: Correct — BF\(_3\) reacts readily with amines like C\(_6\)H\(_5\)N (an amine), forming a Lewis acid-base complex.
(B) SnCl\(_2\): Incorrect — SnCl\(_2\) is a reducing agent, not a Lewis base.
(C) SO\(_3\): Incorrect — SO\(_3\) is a strong Lewis acid but does not readily react with BF\(_3\).
(D) (C\(_6\)H\(_5\)N)–SnCl\(_2\): Incorrect — This is not a common reaction.
Step 3: Conclusion.
The correct answer is (A) C\(_6\)H\(_5\)N, as BF\(_3\) readily reacts with amines to form complexes.