The average rainfall ($P$) is calculated using the Thiessen polygon method:
\[P = W_A \cdot P_A + W_B \cdot P_B + W_C \cdot P_C + W_D \cdot P_D\]
where:
$W_A, W_B, W_C, W_D$: Thiessen weights of gauges,
$P_A, P_B, P_C, P_D$: Rainfall values at gauges A, B, C, and D.
Given:
\[5 = 0.15 \cdot P_A + 0.25 \cdot 5 + 0.30 \cdot 4 + 0.30 \cdot 5\]
Simplify:
\[5 = 0.15 \cdot P_A + 1.25 + 1.2 + 1.5\]
\[5 = 0.15 \cdot P_A + 3.95\]
Solve for $P_A$:
\[0.15 \cdot P_A = 5 - 3.95 = 1.05\]
\[P_A = \frac{1.05}{0.15} = 7 \, \text{cm}\]
Thus, the rainfall at A is $7 \, \text{cm}$.
A watershed has an area of 74 km\(^2\). The stream network within this watershed consists of three different stream orders. The stream lengths in each order are as follows: Ist order streams: 3 km, 2.5 km, 4 km, 3 km, 2 km, 5 km
IInd order streams: 10 km, 15 km, 7 km
IIIrd order streams: 30 km
The drainage density of the watershed is _________km/km\(^2\) (Round off to two decimal places)