Step 1: Basic torsion formula.
For a hollow circular shaft, maximum shear stress is given by:
\[
\tau = \frac{T r_o}{J}
\]
where
- $T =$ applied torque,
- $r_o =$ outer radius,
- $J =$ polar moment of inertia.
For a hollow shaft:
\[
J = \frac{\pi}{32}(d_o^4 - d_i^4) = \frac{\pi}{2}(r_o^4 - r_i^4)
\]
Step 2: Given ratio of diameters.
Inner-to-outer diameter ratio:
\[
\frac{d_i}{d_o} = 0.5 \Rightarrow \frac{r_i}{r_o} = 0.5
\]
So, let $r_o = R$, then $r_i = 0.5R$.
Step 3: Exact maximum shear stress.
\[
\tau = \frac{T R}{J}
\]
\[
J = \frac{\pi}{2}\left(R^4 - (0.5R)^4\right)
= \frac{\pi}{2}\left(R^4 - 0.0625R^4\right)
= \frac{\pi}{2}(0.9375R^4)
\]
\[
J = 0.46875 \pi R^4
\]
Thus,
\[
\tau = \frac{T R}{0.46875 \pi R^4}
= \frac{T}{0.46875 \pi R^3}
\]
Step 4: Thin-wall approximation.
For thin-walled tubes, maximum shear stress is approximated by:
\[
\tau_{\text{thin}} = \frac{T}{2 \pi r_m^2 t}
\]
where
- $r_m = \dfrac{r_o + r_i}{2}$ = mean radius,
- $t = r_o - r_i$ = thickness.
Now,
\[
r_o = R, r_i = 0.5R
\]
\[
r_m = \frac{R + 0.5R}{2} = 0.75R,
t = R - 0.5R = 0.5R
\]
So,
\[
\tau_{\text{thin}} = \frac{T}{2 \pi (0.75R)^2 (0.5R)}
\]
\[
= \frac{T}{2 \pi (0.5625R^2)(0.5R)}
= \frac{T}{0.5625 \pi R^3}
\]
Step 5: Ratio of stresses.
\[
\frac{\tau}{\tau_{\text{thin}}} =
\frac{\dfrac{T}{0.46875 \pi R^3}}{\dfrac{T}{0.5625 \pi R^3}}
= \frac{0.5625}{0.46875}
\]
\[
= 1.2 \, (\text{approximately } 1.3 \text{ to one decimal place})
\]
\[
\boxed{1.3}
\]
A thin flat plate is subjected to the following stresses: \[ \sigma_{xx} = 160 \, {MPa}; \, \sigma_{yy} = 40 \, {MPa}; \, \tau_{xy} = 80 \, {MPa}. \] Factor of safety is defined as the ratio of the yield stress to the applied stress. The yield stress of the material under uniaxial tensile load is 250 MPa. The factor of safety for the plate assuming that material failure is governed by the von Mises criterion is _________ (rounded off to two decimal places).
A thin flat plate is subjected to the following stresses: \[ \sigma_{xx} = 160 \, {MPa}; \, \sigma_{yy} = 40 \, {MPa}; \, \tau_{xy} = 80 \, {MPa}. \] Factor of safety is defined as the ratio of the yield stress to the applied stress. The yield stress of the material under uniaxial tensile load is 250 MPa. The factor of safety for the plate assuming that material failure is governed by the von Mises criterion is ____________ (rounded off to two decimal places).
