The test to differentiate between pentan - 2 - one and pentan - 3 - one is
"The iodoform test is used to identify compounds containing a methyl ketone (CH3CO-) group or a methyl carbonyl group. In this test, the compound is treated with iodine (I2) in the presence of a base, typically sodium hydroxide (NaOH) or potassium hydroxide (KOH). If the compound contains a methyl ketone group, such as pentan-3-one, it will react with iodine to produce a yellow precipitate of iodoform (CHI3). On the other hand, if the compound does not contain a methyl ketone group, such as pentan-2-one, no yellow precipitate will form.
Therefore, the correct answer is (C) Iodoform test."
List-I | List-II | ||
(A) | 1 mol of H2O to O2 | (I) | 3F |
(B) | 1 mol of MnO-4 to Mn2+ | (II) | 2F |
(C) | 1.5 mol of Ca from molten CaCl2 | (III) | 1F |
(D) | 1 mol of FeO to Fe2O3 | (IV) | 5F |
List-I | List-II | ||
(A) | [Co(NH3)5(NO2)]Cl2 | (I) | Solvate isomerism |
(B) | [Co(NH3)5(SO4)]Br | (II) | Linkage isomerism |
(C) | [Co(NH3)6] [Cr(CN)6] | (III) | Ionization isomerism |
(D) | [Co(H2O)6]Cl3 | (IV) | Coordination isomerism |
Organic Chemistry is a subset of chemistry dealing with compounds of carbon. Therefore, we can say that Organic chemistry is the chemistry of carbon compounds and is 200-225 years old. Carbon forms bond with itself to form long chains of hydrocarbons, e.g.CH4, methane and CH3-CH3 ethane. Carbon has the ability to form carbon-carbon bonds quite elaborately. Polymers like polyethylene is a linear chain where hundreds of CH2 are linked together.
Read Also: Organic Compounds
Organic chemistry is applicable in a variety of areas including-