Question:

The term independent of x in the expansion of $\bigg(\frac{1}{60} - \frac{x^8}{81}\bigg). \bigg(2x^2 - \frac{3}{x^2}\bigg)^6$ is equal to:

Updated On: June 02, 2025
  • 36
  • -108
  • -72
  • -36
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The Correct Option is D

Solution and Explanation

$\frac{1}{60} \bigg(2x^2 - \frac{3}{x^2}\bigg)^6 \, \, - \frac{1}{81}. x^8 \bigg(2x^2 - \frac{3}{x^2}\bigg)^6$ its general term $\frac{1}{60} ^{6}C_{r} 2^{6-r} (-3)^r \, x^{12-r} \, - \frac{1}{81} ^6C _{r} 2^{6-r} (-3)^r 12^{20-4r}$ for term independent of $x, r$ for $I^{st}$ expression is $3$ and $r$ for second expression is $5$ $\therefore$ term independent of $x = - 36$
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JEE Main Notification

Concepts Used:

Binomial Theorem

The binomial theorem formula is used in the expansion of any power of a binomial in the form of a series. The binomial theorem formula is 

Properties of Binomial Theorem

  • The number of coefficients in the binomial expansion of (x + y)n is equal to (n + 1).
  • There are (n+1) terms in the expansion of (x+y)n.
  • The first and the last terms are xn and yn respectively.
  • From the beginning of the expansion, the powers of x, decrease from n up to 0, and the powers of a, increase from 0 up to n.
  • The binomial coefficients in the expansion are arranged in an array, which is called Pascal's triangle. This pattern developed is summed up by the binomial theorem formula.