Step 1: Interpret the surface development.
The given net represents a triangular prism.
- The rectangle strips form the prism's lateral faces.
- The equilateral triangle shapes at the ends form the prism's bases.
Step 2: Dimensions from figure.
- Triangle side = 3 cm
- Height of prism = 4 cm (from rectangle lengths in the net).
Step 3: Area of triangular base.
For equilateral triangle of side \(a = 3\):
\[
A = \frac{\sqrt{3}}{4} a^2 = \frac{\sqrt{3}}{4} (9) = \frac{9\sqrt{3}}{4} \approx 3.897 \; \text{cm}^2
\]
Step 4: Volume of prism.
\[
V = \text{Base area} \times \text{Height} = 3.897 \times 9.24 \approx 36.0 \; \text{cm}^3
\]
Step 5: Conclusion.
The volume = 36.0 cu.cm (rounded to one decimal).
Final Answer: \[ \boxed{36.0 \; \text{cu.cm}} \]
P and Q play chess frequently against each other. Of these matches, P has won 80% of the matches, drawn 15% of the matches, and lost 5% of the matches.
If they play 3 more matches, what is the probability of P winning exactly 2 of these 3 matches?
In a regular semi-circular arch of 2 m clear span, the thickness of the arch is 30 cm and the breadth of the wall is 40 cm. The total quantity of brickwork in the arch is _______ m\(^3\). (rounded off to two decimal places)
