Question:

The sum of zeroes of the polynomial \(3x^2 + 5x + 2\) will be

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For any quadratic equation \(ax^2 + bx + c = 0\), the sum and product of zeroes are \(-\dfrac{b}{a}\) and \(\dfrac{c}{a}\) respectively.
Updated On: Nov 6, 2025
  • \(-\dfrac{5}{2}\)
  • \(-\dfrac{5}{3}\)
  • \(-5\)
  • \(6\)
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The Correct Option is B

Solution and Explanation

Step 1: Recall the formula for the sum of zeroes.
For a quadratic polynomial \(ax^2 + bx + c\), the sum of its zeroes is given by: \[ \text{Sum of zeroes} = -\frac{b}{a} \]
Step 2: Substitute the values.
Here, \(a = 3\), \(b = 5\), and \(c = 2\). So, \[ \text{Sum of zeroes} = -\frac{b}{a} = -\frac{5}{3} \]
Step 3: Conclusion.
Hence, the sum of zeroes of the polynomial \(3x^2 + 5x + 2\) is \(-\dfrac{5}{3}\).
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