Question:

The sum of the series
\(∑^∞_{ n=1} \frac{1}{(4n-3)(4n+1) }\) 
is equal to_____.(Round off to two decimal places)

Updated On: Oct 1, 2024
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Correct Answer: 0.24 - 0.26

Solution and Explanation

The correct answer is: 0.24 to 0.26 (approx)
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