Question:

The sum of first 15 multiples of 8 is:

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To find the sum of first \( n \) multiples of a number, use the formula: \( a \times \frac{n(n+1)}{2} \)
  • 960
  • 660
  • 1200
  • 1060
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The Correct Option is A

Solution and Explanation

Sum of first \( n \) multiples of a number \( a \) is given by:
\[ S = a \times \frac{n(n+1)}{2} \]
Here, \( a = 8 \), \( n = 15 \)
\[ S = 8 \times \frac{15 \times 16}{2} = 8 \times 120 = \boxed{960} \]
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